![The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$ The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$](https://www.vedantu.com/question-sets/81a6a607-6f3b-42d1-bdc3-6feedb76da524897162654211039244.png)
The value of $\\int\\limits_\\pi ^{2\\pi } {[2\\sin x]dx} $ is equal to (where[.] is the G.I.F.)A. $ - \\pi $B. $ - 2\\pi $C. $ - \\dfrac{{5\\pi }}{3}$D. $\\dfrac{{5\\pi }}{3}$
![10-3 Find Circumference and Area of Circles 2pi radius pi Diameter Geometry Mathgotserved accuplac - YouTube 10-3 Find Circumference and Area of Circles 2pi radius pi Diameter Geometry Mathgotserved accuplac - YouTube](https://i.ytimg.com/vi/CS-E0geeBuk/maxresdefault.jpg)
10-3 Find Circumference and Area of Circles 2pi radius pi Diameter Geometry Mathgotserved accuplac - YouTube
![Let f: X→ Y be a function defined by f(x) = a sin (x + pi4 ) + b cos x + c . If f is both one - one and Let f: X→ Y be a function defined by f(x) = a sin (x + pi4 ) + b cos x + c . If f is both one - one and](https://dwes9vv9u0550.cloudfront.net/images/2251989/f8a0158c-0f53-40dd-ba5f-0b081dab034d.jpg)
Let f: X→ Y be a function defined by f(x) = a sin (x + pi4 ) + b cos x + c . If f is both one - one and
![The area enclosed by the circle x2+y2=2 is equal toa 4 π sq. unitsb 22 π sq. unitsc 4 π2 sq. unitsd 2 π sq. units The area enclosed by the circle x2+y2=2 is equal toa 4 π sq. unitsb 22 π sq. unitsc 4 π2 sq. unitsd 2 π sq. units](https://search-static.byjusweb.com/question-images/img/study_content/content_ck_images/images/Q34_Pg20_6_20MCQ.png)
The area enclosed by the circle x2+y2=2 is equal toa 4 π sq. unitsb 22 π sq. unitsc 4 π2 sq. unitsd 2 π sq. units
![SOLVED: 1. ∫0^(π)/(2)sin ^6 x d x 2. ∫0^(π)/(2)sin ^10 x cos ^7 x d x 3. ∫0^(π)/(2)sin ^12 2 θcos 2 θ d θ 4. ∫0^(π)/(2)cos ^5 y sin ^6 y d y SOLVED: 1. ∫0^(π)/(2)sin ^6 x d x 2. ∫0^(π)/(2)sin ^10 x cos ^7 x d x 3. ∫0^(π)/(2)sin ^12 2 θcos 2 θ d θ 4. ∫0^(π)/(2)cos ^5 y sin ^6 y d y](https://cdn.numerade.com/ask_images/66834144d0ea4786a19daaef06c1b363.png)