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Find the principal value of tan^(-1){sin(-pi/2)}
sin(pi/10) + sin(13pi/10) is equal to (1) 1/2 (2) -1/2 (3) -1/4 (4) 1 - Sarthaks eConnect | Largest Online Education Community
\cos(\frac{%CF%80}{10})&line2=\mathrm{Solution:\:}\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{8} "sin(pi/(10))cos(pi/(10))")
sin(pi/(10))cos(pi/(10))
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graph of y = 1/2 sin (x pi/2) | mathtestpreparation.com
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prove that sin π/10 + sin 13π/10= -1/2guys plz help...asap... - Brainly.in
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![SOLVED: Entered Answer Preview Result [(pi"[e^ (-pi*s)MV([(s^2)+(pi^2)] [(s^ 2)+9]1]+ [p([(s^2)+(pi^2)]*[(s^2)+911] incorrect + 12 ) (s2 +9) 72 +32) +9) (t-pi) " ([pi(pi^2)]-9)*[(1/3)*sin(3)*(t-pi)- (Ipi) sin(pi)"(t-pi)]+(pi (pi^ 2)-9])*[(1/3)*sin(3t ...](https://cdn.numerade.com/ask_images/0f6b64aaa71d4953add664ff5382ce76.jpg "SOLVED: Entered Answer Preview Result [(pi\"[e^ (-pi*s)MV([(s^2)+(pi^2)] [(s^ 2)+9]1]+ [p([(s^2)+(pi^2)]*[(s^2)+911] incorrect + 12 ) (s2 +9) 72 +32) +9) (t-pi) \" ([pi(pi^2)]-9)*[(1/3)*sin(3)*(t-pi)- (Ipi) sin(pi)\"(t-pi)]+(pi (pi^ 2)-9])*[(1/3)*sin(3t ...")
SOLVED: Entered Answer Preview Result [(pi"[e^ (-pi*s)MV([(s^2)+(pi^2)] [(s^ 2)+9]1]+ [p([(s^2)+(pi^2)]*[(s^2)+911] incorrect + 12 ) (s2 +9) 72 +32) +9) (t-pi) " ([pi(pi^2)]-9)*[(1/3)*sin(3)*(t-pi)- (Ipi) sin(pi)"(t-pi)]+(pi (pi^ 2)-9])*[(1/3)*sin(3t ...
sin(pi/10)+sin(13pi/(10)))(cos^2(pi/6)-cos^2(pi/(10)))` is equal to - YouTube
Value of Sin 180 Degrees (How to Find Sin π value)
Solved E^j pi = cos pi + j sin pi = -1 + 0 = -1 e^j pi = 1 < | Chegg.com
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Art of Problem Solving
Content - Graphing the trigonometric functions
If theta = pi/2, determine the exact value of sin theta. | Homework.Study.com
