![Evaluate sin(pi/6 + sin^-1 (-1/2) ) - Maths - Inverse Trigonometric Functions - 16661935 | Meritnation.com Evaluate sin(pi/6 + sin^-1 (-1/2) ) - Maths - Inverse Trigonometric Functions - 16661935 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_60a28e6d02bef.jpg)
Evaluate sin(pi/6 + sin^-1 (-1/2) ) - Maths - Inverse Trigonometric Functions - 16661935 | Meritnation.com
Prove the following (i) cos(π/2 + x) = - sinx (ii) sin(π/2 + x) = cosx - Sarthaks eConnect | Largest Online Education Community
![trigonometric polynomials - Solutions of equation $\sin \pi x_1\sin \pi x_2=\sin \pi x_3\sin \pi x_4$ - MathOverflow trigonometric polynomials - Solutions of equation $\sin \pi x_1\sin \pi x_2=\sin \pi x_3\sin \pi x_4$ - MathOverflow](https://i.stack.imgur.com/eBuTx.jpg)
trigonometric polynomials - Solutions of equation $\sin \pi x_1\sin \pi x_2=\sin \pi x_3\sin \pi x_4$ - MathOverflow
![Prove that: sin(pi+x)cos (pi2+x)tan (3pi2-x)cot(2pi-x)sin(2pi-x)cos(2pi-x) ( - x)sin (3pi2-x) = n pi + pi 4 where n∈ N Prove that: sin(pi+x)cos (pi2+x)tan (3pi2-x)cot(2pi-x)sin(2pi-x)cos(2pi-x) ( - x)sin (3pi2-x) = n pi + pi 4 where n∈ N](https://haygot.s3.amazonaws.com/questions/1493551_1665197_ans_f6a00f3a652f4aad8e28e1b0fda724df.jpg)